tag:blogger.com,1999:blog-3719647036719810622.post8339548114820306018..comments2023-05-31T04:13:20.113-05:00Comments on Pre-Cal 40S (Winter '07): Absolutely!Darren Kuropatwahttp://www.blogger.com/profile/08462283847470560887noreply@blogger.comBlogger6125tag:blogger.com,1999:blog-3719647036719810622.post-83182497920849902632007-03-02T00:02:00.000-06:002007-03-02T00:02:00.000-06:00Great post and good eye VincentGreat post and good eye VincentGrey-Mhttps://www.blogger.com/profile/10237241798100727258noreply@blogger.comtag:blogger.com,1999:blog-3719647036719810622.post-79532460026413156522007-03-01T22:46:00.000-06:002007-03-01T22:46:00.000-06:00good job on the post..I like the detail you put in...good job on the post..I like the detail you put into graphing those functions on the calculator...clever title as well =)aichelle s.https://www.blogger.com/profile/17302966674461415089noreply@blogger.comtag:blogger.com,1999:blog-3719647036719810622.post-71820724588670200762007-03-01T22:36:00.000-06:002007-03-01T22:36:00.000-06:00I was right? WOW I really thought I didn't make an...I was right? WOW I really thought I didn't make any sense.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3719647036719810622.post-78848738044047968522007-03-01T21:03:00.000-06:002007-03-01T21:03:00.000-06:00Yes you're right Vince! Sorry about that, I guess ...Yes you're right Vince! Sorry about that, I guess I got carried away. XD Thanks for noticing the error. OUTPUTS are the ones changed to positive, not the inputs (x values).♫ Jann ♫https://www.blogger.com/profile/15160058223354491484noreply@blogger.comtag:blogger.com,1999:blog-3719647036719810622.post-43081705944273889152007-03-01T20:36:00.000-06:002007-03-01T20:36:00.000-06:00Great post though! It's concise and comprehendable...Great post though! It's concise and comprehendable! It's just that one little area where I got perplexed.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3719647036719810622.post-78341457967248533342007-03-01T20:35:00.000-06:002007-03-01T20:35:00.000-06:00Hey Jann, you mentioned, "The absolute value chang...Hey Jann, you mentioned, <I>"The absolute value changes the negative input of the graph into a positive input. Where x<0, the negative inputs were changed into positive inputs</I>." I thought it was the outputs or the <I>y</I>-values that become positive. Let's say it's <I>y = |x|</I> and we substitute -3 to <I>x</I>. Wouldn't <I>y</I> become 3 and not <I>x</I> since it's -3? So the new coordinates would be (-3,3). I may not be making any sense at all. But I thought I learned that it's the y-values that become positive on an aboslute value graph. Also if we look at <I>y = |2x+4|</I>. If <I>x</I> = -2, then y would be 2(-2) + 4 = 0, and not 2(2) + 4 = 8. I don't know if I make sense here but in the first solution, we substitute -2 for x and not |-2| for x. Therefore, it is the y values or OUTPUTS that turn into positive values on absolute value functions when they were negatives to begin with. I hope you get me and I'm not sure if I'm making sense. Tell me if I learned it wrong. Thanks!Anonymousnoreply@blogger.com