Scribe

Hello everyone! Sorry again for the late scribe. I just really needed some more time to study before the exam today. Hopefully everyone did a super good job on it! =D


Well, on Friday, if I remember correctly was review for the exam on Logarithms and Exponents, Probability and Trigonometric Identities. The reviews are done the exact same way we do our pretests! All the questions and answers are on the slides. Click here.

The exam is pretty much over so it's kind of a relief for all of us. There's still classes tomorrow!! Scribe for tomorrow shall be.....




I think the it's a new cycle, so I chooose.. Vincent!

- Sandy <3

PreCalculus: The Last Bob.

This unit comes to an end and so does the year. As of today there is exactly one week left before our final exam. Is anyone as excited as i am? I'm kidding, of course! Well, this unit has been okay... sort of. I'm not too sure I'm that great at it yet. However, tonight should help a bit! Lots of studying. Fortunately I have nothing else to worry about except pre cal now. So gives me a great opportunity to practice more. Since practice makes perfect. Back to sequences, though. I'm not too sure if this unit test is going to be as good to me as the others. Hopefully I'm able to do just as well as the other times. Good luck to everyone! Hopefully you guys do very good as well. (:

99.9 BOB FM! (8)

Every single time I arrive on our blog I think about how close the provincial exam is. 2 weeks from tomorrow! It's really time to start studying. As for this unit, I didn't do great on my quiz, but the mistakes were really dumb. -_-" As soon as I seen the correct answer I realized I had made a stupid mistake. Regardless of the quizzes, I think this unit is pretty straight forward and not that difficult at all. I hope to do as good on this test as my logs one. (: Hopefully everyone else does really good as well. Good luck to everyone with the up coming test! <3

Congratulations!!

Well.. since our homeroom does contain 3 out of 4 candidates for the school elections this year... I think this blog deserves this post.

Congratulations to Richard who is next years wonderful President!
and... Congratulations to Vincent who is next years wonderful Vice-President!

You guys worked hard and you both deserve your positions on the executive council. I'm definitely looking forward to next year with you two. (:

So again, congratulations to the both of you. =)

Happy Mother's Day, BOB.

So here's my sixth bob so far this year. Conics, has actually been fun. (: Math is fun if you know what you're doing and understand it. Haha, it's weird but true. This unit has been pretty straight forward. I just have to remember to look at the question completely before drawing a graph. That's where i usually make my mistakes. -_-" But other than that i understand the concepts and everything. I think this test is going to be a good one. (: I don't have much else to say. Good luck everyone on the pre test and test tomorrow! =D

BOB 5

Yet another BOB. Well.. this unit has definately been challenging near the end. I guess it obviously shows from my pre test. -_-" But on the bright side, I have all of tonight to study even more! Out of everything we've learnt this unit, I think the poker probability part was the hardest for me. Either, it's difficult to begin with... or missing a majority of that class had a lot to do with it. Practice makes perfect, so hopefully I get better at it. :\ There isn't a lot to say. I just hope we all do really well on this test! I know I want to. (: Well, good luck everyone on the Counting test tomorrow morning. (: Oh.. and lets enjoy our afternoon off too. Tehe. =D

Toodle-loo Kangaroo.

Counting

HI guys! I'm Sandy and I'm once again scribe for today. I just wanted to say THANK YOU so much John for volunteering to be scribe for Thursday when I needed someone. I'd also like to apologize for the scribe post being up late. It's been a rough weekend, so again, my apologies.

MORNING:

At the beginning of class we talked about different things we could do for our DEV Projects. To make fancy fractions like Mr. K makes on Apple Works, you can either download MathType or you can use Microsoft Word. Personally, I use Microsoft Word 2007, but I'm not sure if the older versions can do that as well. To upload photos you can use Flickr, most of you know about Photobucket, there's also Fileden, Freewebtown and Prizaar.

Then we started with our lesson!

Follow the butterflies!
You need to make a four letter word. So basically there's 7 letters you can use all together. The first letter you have 7 options to pick from, then one is being used so for the next spot you only have 6 options. Then the next is 5 options and then 4 options.
The red answer is the correct answer. At the beginning there has to be a vowel and at the end there has to be a consonant. Regardless of which letters those are, there a two letters that have to be in each spot. Which means, there's only 5 letters that can go in the second spot and 4 in the other since two are already being used.
Out of the 7 letters, there are 3 consonants and 4 vowels. To make them alternate they either have to be vowel, consonant, vowel, consonant or consonant, vowel, consonant, vowel. So, for the first, once 1 vowel is used the third letter only has 3 options left. Same goes for the consonants, once one consonant is used, there's only 2 options left. Once you've figured it out, you add the two together and it gives you your answer.

When it comes to circles things change a bit. To break it down, the order in which people or objects are placed around a table is the only thing that matters. Rotating them doesn't make a different, frankly they're just in a different position around the table with the exact SAME order. The same person will be on their right and the same person will be on their left. So for these kind of questions the formula to find it is (n-1)! (Where "!" means Factorial not "I really, really mean it"). On this slide the circles in RED are the same and the circles in BLUE are the same.
HOWEVER... tables are different from bracelets. With bracelets, you're able to turn them over. So technically each arrangement actually represents 2 of them. The same applies for necklaces and other things that can be flipped. In these special cases, the formula you use is (n-1)!/2.

With this questions, you can pretty much treat the married couples as ONE person since they always have to be across from each other. Once one sits, the other one has no choice where to sit. So since there are 4 couples, each treated as ONE the answer to this question is (4-1)! --> 3!. Or you can draw it like above.
Since the boys are Gentlemen and we, are the ladies we'll be seated first. So the first lady seated is the reference point and she determines how everyone else can be seated. Therefore they'll be (4-1)!. Now you have four spots left for the men to sit. Since the reference point has already been placed the first spot can be used by 4 men, then the next only has 3 men to sit there and so on and so forth. So the men will be 4!. Multiplying those together you'll arrive at 144.

AFTERNOON:

In the afternoon we were lucky to accompanied by Mr. K children Kas and Emilia! (Who by the way, are soo adorable). Anyway, Emilia sat with me and Kas sat with Aichelle. (: Moving along!


Instead of it being 6!, it's (6)(6)(5)(4)(3)(2)(1). This is because if 0(zero) was the first number, it wouldn't be 5 digit numbers anymore, it would only be a 4 digit number. So for the first number, there's only 6 numbers out of the 7 to use. For the second number, no matter what number the first is, there's also 6 options because the zero can be used there now. Then it decreases from there.
The second question is actually not the correct one. This is:

Basically to make it easy you do one set for 0(zero) and another for the other numbers. For 0, no matter what zero has to be the last number which gives you only 1 option. Then for the first number you have 6 other options. Then so on and so forth. For the second part, you have 3 options but no matter which you pick, you only use 1 of them. The first number HAS to be 5 oppose to 6 like the previous because 0 cannot be the first digit otherwise it won't be a 5 digit number anymore. Then you add the two together. (:
Again, that's the wrong answer and the correct one is this:

It's pretty much like the previous part to this question, but instead of 2, 4 and 6, we use 5, based on what the question asks.

This question originally said, How many necklaces can be made from 12 beads of different colours? Thanks to Jojo and his brilliant mind, we realized the actual answer was 1. With 12 beads of different colour, we can make one necklace. It doesn't specify how many different colours. Then Mr. K changed it! But of course, Jojo gets the credit for recognizing it.
To solve this question is fairly straight forward. You have 12 beads, but it's a circle so the first bead is the reference point. So it's (12-1)! Also, since it's a neckalce, if it's flipped it's the same. Therefore you divide by 2 and there's your answer.

This is a Combination type of question. These are when you arrange objects and don't care what order they're in. However, afterwards you DO care what order they're in. So first you just find the different ways that a necklace of 12 beads can be made with 18 beads. (18!/12!6!) Then, for each of those different ways, you need to find out how many different ways the beads can be arranged. So you multiply it by (12-1)!/2. You simplify and come up with your answers.

Since the students have to be right beside each other everytime (consecutive), there's only 6 ways that they can be arranged in the 8 seats (Shown by Aichelle at the bottom of slide). Since there are 4 students, the first seat has 4 students to sit there, then the next 3, the next 2, and the next only 1. So it's 4! multiplied by the 6 different ways they can sit in the 8 seats.

The 3 books that always have to be together, you should just put into a bag until later on in the question (Mr. K's blue bag). Considering the 3 books in the blue bag as 1, the different ways they can be positioned is 6!. Then, if you take the books out, the different ways the 3 books can be arranged is 3!. Multiplying them together you get the answer. (:

Hopefully I explained everything enough for people to understand. I again apologize for the late post. Usually if I have the weekend I like to post it up on that friday. But since things got in the way, it never happened. So again, sorry.
AND.. the next scribe will be the super awesome girl that sits next to me in class, Mel!

BOB

This semester is going by super fast. Here comes and goes another unit. Honestly, the unit started off quite easy. I missed a day when everyone learnt about how to graph logarithms because I was at the Convention Centre volunteering for the Career Symposium. However, the slides and podcast did help a bit, along with asking questions. (: Other than that, I think this unit test should be a good one. Good luck everyone.

BOB-3

Time is flying and here I am posting another BOB for another test. This unit I've had difficulty with. I found myself struggling a lot during the unit. At first it was hard for me to recognize what equals what. Things like how sin²θ + cos²θ = 1. Now I've managed to recognize them a lot easier. Proving is something I really suck at, too. However, practice makes perfect and the exercises are helping with the things we do in class but I still struggle now and then with things. But hopefully by this weekend and by Monday evening I'll have it down packed and be ready for the test on Tuesday. Yay! Good luck everyone, hopefully we all pass with flying colours. (:

BOB 2

This unit I've had some trouble with. I understand a majority of what needs to be done but these problem solving questions are pulling me down. I'm sure a lot of people feel the same about them. It's not that hard, i just happen to get confused along the way most of the time. But working on it in class is helping me understand how i do these things. I don't have much else to say, but good luck everyone on the pre test and test! ..

Transformations

Good afternoon everyone, I'm Sandy and I'm scribe for today. During today's class we started off by completing the question Mr. K asked us to do yesterday. Just in case you didn't write it down or you're too lazy to scroll down and look for the slide, this was the question:

The pedals on a bicycle have a maximum height of 30cm above the ground and a minimum distance of 8cm above the ground. Jeng pedals at a rate of 20 cycles per minute.
a) What is the period, in seconds for this function?
b) At t = 0, Jeng's right foot is closest to the ground.
i) Write 2 equations that represent the height of her right foot above the ground; 1 sine; 1 cosine.
ii) For how long per cycle is Jeng's right foot 20cm, or higher, above the ground?


To start of, part A of the question was fairly straight forward. To find the period, we take 1 minute and convert it to seconds which is 60 seconds. And to find out how long each cycle took, we divided the time, 60 seconds, by the number of cycles per 60 seconds, which is 20 cycles.
60 seconds
20 cycles
And this results in,
3 seconds per cycle.

For part B, i, we're asked to make up two equations, one for sine, and one for cosine. For some people it might be easy to make the equations, but sometimes it's easier to determine the equations for the function by making a graph of it first.

NOTE: This graph has some errors. For one, when drawing a graph don't forget to label your x and y axis and draw the arrows. For two, don't forget to add arrow(s) or dot(s) to the end of the function depending on the context of the original questions. An example can be time, because time does not go backwards there would be a dot at the point where the function touches the y-axis and an arrow on the other end indicating that the graph continues with time. For three, you should always number at least the 4 points (for your max, min, and where it touches the sinusoidal axis). Usually it's labeled as π/2, π, 3π/2 and 2π. In this question we should label it 0.75, 1.5, 2.25 and 3.

From the graph, it's a lot easier to determine the equations that go with it.
Making a list also helps come up with the equations.
This album is powered by BubbleShare - Add to my blog
It's usually easier to do it in the DABC order. So starting with D, we can easily find it by finding the middle between the max and min value. In this case it's 19. Since the sign is always positive for D, we can put 19 beside D for both sine and cosine. For A, we simply find the distance from either the max or min, depending on what you prefer, to the sinusoidal axis. For this question A is 11. The sign for A we don't know yet, but we'll come back to that afterwards. The period, which we calculated earlier (3), is the same for both sine and cosine so we can place that where B is. For C, we're looking for a phase shift. For cosine we know that the max or min value starts at the y-axis.. therefore C for cosine is 0. Knowing this, we can figure out the sign of A, which in this case is negative (-) because cosine is starting at it's min. For sine, we know that there has been a phase shift of 0.75 and it's moved to the right so C for sine is +0.75. We can tell from the graph that A for sine is positive so parameter A is +11.

Part B, ii, we can do on our calculator. First we take the equation we made and put it into Y₁. Then for Y₂ we put in a 20.

Now that we've done that, we find the intersection of Y₂ and the function -11cos((2π/3)x)+19.

The first intersection was 0.7935 and the second intersection was 2.2065. To find the amount of time that Jeng's foot is 20cm or higher above the ground we subtract 0.7935 from 2.2065 and we end up with 1.4131. 1.4131 is the amount of time that Jeng's foot is 20cm or higher above the ground. Wasn't that easy?

Well we started another question in class today, but I'll leave that for Danny to do tomorrow since we're not even close to being finished it. Homework will be posted on the blog if it hasn't already and during tomorrow's morning class we'll be completing the question we started today. Hope you enjoy the rest of early dismissal!. (: Tootles.

BOB

I kind of figured that pre calculus 40s was going to be more challenging than pre calculus 30s and i was right. this first unit i kind of struggled with at first whether it be because i was sick and didn't feel like absorbing anything or listening in class or because it was just tough to begin with. At first i was having trouble with the unit circle and understanding it but i soon figured it out. Graphing was another thing i had some trouble with but it's improving thanks to the group work. Everything else seems to be pretty good. Well, that's all i have to say. Good luck on the test tomorrow! Tootles (: