## Sunday, May 27, 2007

### Probability

Friday is grueling days ever because of 2 unexpected quizzes from Mr.K

First we started-off with this. The very first thing to do is to make a tree diagram and fill out the probability for each cases .The probability that Tony will move t
o Winnipeg is 2/9, and the probability he will marry Angelina if he moves to Winnipeg is 9/20, all you need to do is to multiply to the probability that Tony will move to Winnipeg and marry Angelina.To get this, all you need to do is to multiply the probability that he is moving to Winnipeg which is 2/9 and the probability that he is not marrying Angelina 11/20.
To get this multiply the probability that he is staying which is 7/9 and the probability that he is not marrying Angelina which is 19/20.This is the probability of drawing four aces in a standard deck of fifty-two cards.
This is the probability of drawing diamond cards.
This is the probability of drawing an ace and a diamond.
All you need to do is to add the probability of drawing four aces and diamond cards, then subtract the probability of drawing an ace and a diamond.
To answer this question, you need to make a Venn Diagram. Then from that diagram you will see that ten out of twenty-five students doesn't like either Dr.Pepper or Diet Dr.Pepper.

This is the probability of choosing two green dresses out of six.
This is the probability of choosing four dresses out of nine.
This is the probability of choosing six dresses out of fifteen.
All you need to do is just by dividing the favourable cases over the possible outcomes.

First thing is to make a tree diagram and fill out the probability for each cases. Next is to get the probability of an SUV that has air conditioning and divide it by the probability of having a passenger car that has air conditioning plus the probability of an SUV that has air conditioning.

To get this, just add the probability of drawing a defective blade first and then a good blade and the probability of drawing a good blade first and then a defective blade.
For the 1st question, you can't use the number 0 as the first digit, so you nine choices left.
The 2nd digit, you can't pick the same number that you use before so you have nine choices left. The 3rd digit , you can't pick the same number that you use for the 1st and 2nd digit, so you have 8 choices left. The 4th digit, you can't pick the same number that you use from the previous three, so you have 7 choices left.

For the 2nd question, just divide the possibility of having an odd number by the total number of possible digits.

For the 3rd question, break the question into 2 steps,one is that ending in zero and the other is ending in 5, then add both . Then divide the answer by the total number of th
e possible digits.

To get this, get the probability of getting exactly four hits out of 6 throws. Then, raise the probability of hitting to the fourth power and then the probability of missing to the second power.

That's it folks.By the way we have a pre-test tomorrow,sorry for the late scribe .The next scribe is DINO.