Wednesday, February 28, 2007

TODAY ,TODAY

Well today was an interesting day as we all know. Well it started off with Mr.K acknowledging that when some of us attempted the homework we ran into problems as Aichelle posted. So that was basically what our class was about. We went over the things that Mr. K hurriedly tried to teach in a mere fifteen minutes. With that said I think he did a pretty good job considering the time frame the had to do it in. So back to business...

First thing we kinda went over today was an efficient way to graph our functions and their reciprocals. As the first slide of today's class shows is an order that we can use in order to help us graph. Also Mr.K said that you don't necessarily have to follow that order but should do so always with #1 and 2.

  • Number 1 on the table that was shown to us was to find the variant points which is in when y equals 1 or -1 on the graph drawn.
**remember not to try to move the variant point so that it is 1 or -1 on the x-axis b/c the variant point directly relates to the y-axis.**


  • Number 2 on the table was to find the asymptotes, which was when y=0 on the x-axis on the drawn graph. Where the asymptotes are on the graph there must be a dotted line .
**remember that there will not always be asymptotes**


These two steps should always go first.
The order in which you do the other steps doesn't matter.
Step4 and 5 are to determine whether the reciprocal graph is bigger or smaller



f(x)=x+2 1/f(x)=1/x+2

Sorry my dots are hard to see but there are two blue dots at the variant points and the red circle is where the asymptote is located.

So based on the steps that we got more information on we learned:
Step1: The variant points on the graph are located at (-1,1) and (1,3) in which those points will be on both graphs
Step2: The asymptote is on the line x=0 so that is where the reciprocal graphs cannot touch
Step3: from the variant point to the asymptote on the left side of the graph the y coordinates are biggering negatively so on the reciprocal graph they are smallering negatively.
from the variant point to the asymptote on the right side of the graph the y coordinates are smallering so on the reciprocal graph they are biggering.
Step 4: from the variant point on the left side of the graph to infinite the y-coordinates are biggering negatively so on the reciprocal they are smallering negatively
from the variant point on the right side of the graph to infinite the y-coordinates are biggering so the reciprocal y coordinates are smallering.

Another thing that we learned when we tried to graph the reciprocal of
x²+1 which is f(x)=1/x²+1

Was the The witch of Agnesi which was mistranslated from greek into latin which was supposed to be the curve. The curve of Agnesi. Maria Gaetana Agnesi had written a book on math for her younger brothers which had become the first surviving mathematical work written by a female.
To Find more about Ms. Angesi
http://mathworld.wolfram.com/WitchofAgnesi.html

Well was pretty much it for what we did in class b/c we were interrupted. Ms.Stawski our guidance counselor came into class and distributed registration forms for next year.
Funny thing she told us to make sure we have all our credits and that they are all counted for b/c I actually went down to the guidance office and I was missing a credit I earned in grade 9 when I came from the U.S. well that's all folks. Not a long post huh? sorry and the next scribe is .......drumroll........jann.
Bye guys



2 comments:

aichelle s. said...

good job Lauressa...thanks for the reminders.

Mr. Kuropatwa said...

As you noted in the subsequent post there are some errors here as a result of not using brackets.

Any chance you might "fix" this post? ;-)